**Jacquard circular knitting machine: **

Production of a jacquard circular knitting machine is disclosed provided with a needle cylinder driving mechanism capable of optionally and readily controlling the rotary motion of the needle cylinder according to the pattern to be knitted.

**Find Out the Production of Jacquard Circular Knitting Machine**

Two-color jacquard fabric is to be produced, and the following machine and fabric data were assumed:

**Example-1:
**

**Values of circular knitting machine:**

Machine diameter = 26”

Gauge E = 20

Number of feeders = 60

Machine speed = 27rpm

Machine efficiency = 80%

**Values of article:**

**Structure:** two-color jacquard (two-part Courses for one course)

**Yarn:** cotton yarn Nm = 50/1(80%), polyester filament yarn dtex = 67f14 (20%)

Course density = 10.5courses /cm.

Wales density = 16wales /cm.

Fabric weight = 90gm /m2

We know that,

……………………………………………………………………………….n X S X 60 X ŋ

Machine performance L in meter per hour = ……………………………………………………

………………………………………………………………..feeders/course X courses/cm X 100

…27 X 60 X 60 X 0.80

= …………………………….

…….2 X 10.5 X l00

= 37 m/hr.

……………………………………………D X π X E

Fabric width, WB in meter = …………………..

………………………………………….wpcm X 100

….26 X 3.14 X 20

= ……………………..

…….16 X 100

= 1.02 m

…………………………………………………………L X WB X Weight in GSM

Machine performance in Kg per hour = ………………………………………

……………………………………………………………………….1000

….37 X 1.02 X 90

= ……………………..

……….1000

= 3.396 Kg/hr

**Example-2:**

**Values of circular knitting machine:**

Machine diameter = 30”

Gauge E = 20

Number of feeders = 96

Machine speed = 23rpm

Machine efficiency = 80%

**Values of article:**

**Structure:** three colour jacquard

**Yarn:** polyester dtex = 150/1

Course density = 12 courses/cm.

Wales density = 11wales/cm.

Fabric weight = 180gm/m2

………………………………………………………………………….n X S X 60 X ŋ

Machine performance L in meter per hour = ……………………………………………………..

…………………………………………………………………feeders/course X courses/cm X 100

…23 X 96 X 60 X 0.80

= …………………………….

…….3 X 12 X 100

= 29.44 m/hr.

……………………………………………D X π X E

Fabric width, WB in meter = ……………………

……………………………………………wpcm X 100

….30 X 3.14 X 20

= …………………….

……..11 X l00

= 1.7m

…………………………………………………………L X WB X Weight in GSM

Machine performance in Kg per hour = ………………………………………..

……………………………………………………………………..1000

….29.44 X 1.7 X 18

= ……………………….

………..1000

= 9 Kg/h

**Example-3:**

Calculate the production of a single-jersey circular knitting machine in kg/hr from the following data:

**Values of circular knitting machine:**

Machine diameter = 30”

Gauge E = 28

Number of feeders = 96

Machine speed = 35rpm

Machine efficiency = 80%

**Values of article:**

Structure: plain(Single jersey)

Yarn: cotton Nm 50/1(Ne29.6/1)

Stitch length = 0.25cm

…n X S X(π X d X E X stitch length in cm)X 60 X ŋ X 0.4536

= ………………………………………………………………………………………

………………….100 x l00 X Ne x 840 x 0.9144

…n X S X(d X E X stitch length in cm.) X ŋ

= ……………………………………………..……………. X 0.00001112598

………………………….Ne

….35 X 96 x (30 X 28 X 0.25) X 80

= …………………………………..…………… X 0.00001112598

………………….29.6

=21.22 Kg. (ANS)

Auhtor of this Article:Raju TexKnitting Technologist, B.J.Group, Mawna, Gazipur Chittagong Textile Engineering College Facebook: https://www.facebook.com/ERZRAZU