Jacquard circular knitting machine:
Production of a jacquard circular knitting machine is disclosed provided with a needle cylinder driving mechanism capable of optionally and readily controlling the rotary motion of the needle cylinder according to the pattern to be knitted.
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Find Out the Production of Jacquard Circular Knitting Machine
Two-color jacquard fabric is to be produced, and the following machine and fabric data were assumed:
Example-1:
Values of circular knitting machine:
Machine diameter = 26”
Gauge E = 20
Number of feeders = 60
Machine speed = 27rpm
Machine efficiency = 80%
Values of article:
Structure: two-color jacquard (two-part Courses for one course)
Yarn: cotton yarn Nm = 50/1(80%), polyester filament yarn dtex = 67f14 (20%)
Course density = 10.5courses /cm.
Wales density = 16wales /cm.
Fabric weight = 90gm /m2
We know that,
……………………………………………………………………………….n X S X 60 X ŋ
Machine performance L in meter per hour = ……………………………………………………
………………………………………………………………..feeders/course X courses/cm X 100
…27 X 60 X 60 X 0.80
= …………………………….
…….2 X 10.5 X l00
= 37 m/hr.
……………………………………………D X π X E
Fabric width, WB in meter = …………………..
………………………………………….wpcm X 100
….26 X 3.14 X 20
= ……………………..
…….16 X 100
= 1.02 m
…………………………………………………………L X WB X Weight in GSM
Machine performance in Kg per hour = ………………………………………
……………………………………………………………………….1000
….37 X 1.02 X 90
= ……………………..
……….1000
= 3.396 Kg/hr
Example-2:
Values of circular knitting machine:
Machine diameter = 30”
Gauge E = 20
Number of feeders = 96
Machine speed = 23rpm
Machine efficiency = 80%
Values of article:
Structure: three colour jacquard
Yarn: polyester dtex = 150/1
Course density = 12 courses/cm.
Wales density = 11wales/cm.
Fabric weight = 180gm/m2
………………………………………………………………………….n X S X 60 X ŋ
Machine performance L in meter per hour = ……………………………………………………..
…………………………………………………………………feeders/course X courses/cm X 100
…23 X 96 X 60 X 0.80
= …………………………….
…….3 X 12 X 100
= 29.44 m/hr.
……………………………………………D X π X E
Fabric width, WB in meter = ……………………
……………………………………………wpcm X 100
….30 X 3.14 X 20
= …………………….
……..11 X l00
= 1.7m
…………………………………………………………L X WB X Weight in GSM
Machine performance in Kg per hour = ………………………………………..
……………………………………………………………………..1000
….29.44 X 1.7 X 18
= ……………………….
………..1000
= 9 Kg/h
Example-3:
Calculate the production of a single-jersey circular knitting machine in kg/hr from the following data:
Values of circular knitting machine:
Machine diameter = 30”
Gauge E = 28
Number of feeders = 96
Machine speed = 35rpm
Machine efficiency = 80%
Values of article:
Structure: plain(Single jersey)
Yarn: cotton Nm 50/1(Ne29.6/1)
Stitch length = 0.25cm
…n X S X(π X d X E X stitch length in cm)X 60 X ŋ X 0.4536
= ………………………………………………………………………………………
………………….100 x l00 X Ne x 840 x 0.9144
…n X S X(d X E X stitch length in cm.) X ŋ
= ……………………………………………..……………. X 0.00001112598
………………………….Ne
….35 X 96 x (30 X 28 X 0.25) X 80
= …………………………………..…………… X 0.00001112598
………………….29.6
=21.22 Kg. (ANS)
Auhtor of this Article: Raju Tex Knitting Technologist, B.J.Group, Mawna, Gazipur Chittagong Textile Engineering College Facebook: https://www.facebook.com/ERZRAZU