Jacquard circular knitting machine:
Production of a jacquard circular knitting machine is disclosed provided with a needle cylinder driving mechanism capable of optionally and readily controlling the rotary motion of the needle cylinder according to the pattern to be knitted.
Find Out the Production of Jacquard Circular Knitting Machine
Two-color jacquard fabric is to be produced, and the following machine and fabric data were assumed:
Example-1:
Values of circular knitting machine:
Machine diameter = 26”
Gauge E = 20
Number of feeders = 60
Machine speed = 27rpm
Machine efficiency = 80%
Values of article:
Structure: two-color jacquard (two-part Courses for one course)
Yarn: cotton yarn Nm = 50/1(80%), polyester filament yarn dtex = 67f14 (20%)
Course density = 10.5courses /cm.
Wales density = 16wales /cm.
Fabric weight = 90gm /m2
We know that,
……………………………………………………………………………….n X S X 60 X ŋ
Machine performance L in meter per hour = ……………………………………………………
………………………………………………………………..feeders/course X courses/cm X 100
…27 X 60 X 60 X 0.80
= …………………………….
…….2 X 10.5 X l00
= 37 m/hr.
……………………………………………D X π X E
Fabric width, WB in meter = …………………..
………………………………………….wpcm X 100
….26 X 3.14 X 20
= ……………………..
…….16 X 100
= 1.02 m
…………………………………………………………L X WB X Weight in GSM
Machine performance in Kg per hour = ………………………………………
……………………………………………………………………….1000
….37 X 1.02 X 90
= ……………………..
……….1000
= 3.396 Kg/hr
Example-2:
Values of circular knitting machine:
Machine diameter = 30”
Gauge E = 20
Number of feeders = 96
Machine speed = 23rpm
Machine efficiency = 80%
Values of article:
Structure: three colour jacquard
Yarn: polyester dtex = 150/1
Course density = 12 courses/cm.
Wales density = 11wales/cm.
Fabric weight = 180gm/m2
………………………………………………………………………….n X S X 60 X ŋ
Machine performance L in meter per hour = ……………………………………………………..
…………………………………………………………………feeders/course X courses/cm X 100
…23 X 96 X 60 X 0.80
= …………………………….
…….3 X 12 X 100
= 29.44 m/hr.
……………………………………………D X π X E
Fabric width, WB in meter = ……………………
……………………………………………wpcm X 100
….30 X 3.14 X 20
= …………………….
……..11 X l00
= 1.7m
…………………………………………………………L X WB X Weight in GSM
Machine performance in Kg per hour = ………………………………………..
……………………………………………………………………..1000
….29.44 X 1.7 X 18
= ……………………….
………..1000
= 9 Kg/h
Example-3:
Calculate the production of a single-jersey circular knitting machine in kg/hr from the following data:
Values of circular knitting machine:
Machine diameter = 30”
Gauge E = 28
Number of feeders = 96
Machine speed = 35rpm
Machine efficiency = 80%
Values of article:
Structure: plain(Single jersey)
Yarn: cotton Nm 50/1(Ne29.6/1)
Stitch length = 0.25cm
…n X S X(π X d X E X stitch length in cm)X 60 X ŋ X 0.4536
= ………………………………………………………………………………………
………………….100 x l00 X Ne x 840 x 0.9144
…n X S X(d X E X stitch length in cm.) X ŋ
= ……………………………………………..……………. X 0.00001112598
………………………….Ne
….35 X 96 x (30 X 28 X 0.25) X 80
= …………………………………..…………… X 0.00001112598
………………….29.6
=21.22 Kg. (ANS)
Auhtor of this Article: Raju Tex Knitting Technologist, B.J.Group, Mawna, Gazipur Chittagong Textile Engineering College Facebook: https://www.facebook.com/ERZRAZU