# Calculation of Loom Production

What is Loom?
The loom is an apparatus/device for making fabric by weaving yarn or thread. It produces fabric by interlacing a series of length-wise, parallel yarns width a series of width-wise parallel yarns. To get the optimum output of the loom we must know about the loom production calculation. In this article, I have given many examples of the calculation of loom production.

### Calculation of Loom Production

Problem-1:

Production of the loom:

PPM = 200, PPI = 50

Production per loom per minute =200/50 =4”

Production per loom per month = 4 x 60 x 24 x 30 inch

Production per loom per year at 70% efficiency = 4 x 60 x 24 x 30 x 12 x 0.7 inch
= (4 x 60 x 24 x 30 x 12 x 0.7) / 36 yds
= (4 x 60 x 24 x 30 x 12 x 0.7) / 39.37 m
= 36868.68 m (ANS)

Problem-2:

PPM = 350
PPI = 60
No. of loom = 45
Time = 7 days
Efficiency = 90%

Find out production in m?

Solution:

…………………..350………………………………..90………..1
Production = …….. x (60 x 24 x 7) x 45 x …….. x ……….. m
……………………60………………………………..100……39.37

….14288400000
= …………………… m
………236220

= 60487.68 m (ANS)

Problem-3:

PPM = 650
PPI = 58
No. of loom = 10
Time = 35 days
Production = 110000 m

Efficiency = ?

Solution:

……………………..650 x 60 x 24 x 35 x 10 x η
Production = ……………………………………………
…………………………….58 x 100 x 39.37

……………110000 x 58 x 100 x 39.37
=> η = …………………………………………
………………650 x 60 x 24 x 35 x 10

=> η = 76.77% (ANS)

Problem-4:

Find out Wt. of yarn in fabric (warp & weft), from the following specification.

Warp count x Weft count
.……………………………………….x Fabric width
……………..EPI x PPI

or,

..20 x 22
.………….. x 56”
..60 x 58

Solution:

In 5000 m fabric, wt of weft warp,

………60 x 56 x 5000 x 1.05
= ………………………………………. kg
…..0.914 x 840 x 20 x 2.2046

= 521.09 kg (ANS)

In 5000 m fabric, wt of weft,

…..58 x 39.37 x 5000 x 56 x 1.05
= …………………………………………… Kg
……….36 x 840 x 22 x 2.2046

= 457.73 kg (ANS)

Problem-5:
Find out the wt. of required warp & weft to produce 5000m fabric from the following specification.

18 x 16
.…………… x 58”
66 x 62

Solution:

……………………………66 x 58 x 5000 x 1.05 x 1.1
Required warp = ………………………..……………………  =  725.28 kg (ANS)
…………………………….0.9144 x 840 x 18 x 2.0246

…………………………..62 x 39.37 x 5000 x 58 x 1.05 x 1.1
Required weft = ……………………………………….……………….. = 766.49 kg (ANS)
……………………………………36 x 840 x 16 x 2.2046

Problem-6:
Calculate the yarn consumption of a loom per hour running at 180 PPM for producing from the following specification.

….40 x 60
………………. x 56” fabric
….72 x 48

Solution:

…………………………………….180…………..1
Production/hour/loom = ……. X 60 x …….
..……………………………………48…………..36

= 6.25 yd

………………………………….72 x 56 x 6.25 x 1.05 x 1.1
Req. amount of warp = ……………………………………..
…………………………………………840 x 40 x 2.004

= 0.393 Kg

………………………………….48 x 36 x 6.25 x 56 x 1.05 x 1.1
Req. amount of weft = ………………………………………………
……………………………………….36 x 840 x 60 x 2.024

= 0.175 Kg (ANS)

Problem-7:
Calculate the time required to complete a weavers beam having 1000yds of warp on it. The woven cloth is required to have 60 PPI. Loom speed is 200 and efficiency 80%. Assume any missing data.

Solution:

…………………………………….210….60
Production/loom/hour = ……. x ….. x 0.8
……………………………………..60…..36

= 4.67 yds

…………………….Length of cloth from the beam
Time req. = ……………………………………………………
…………………………..Actual production/hr

Length of cloth from the beam,

……………………………………100 – crimp
= (Length in yds of warp x ……………….) – Waste in yards
…………………………………………..100

………………100 – 6
= (1000 x …………….) – 6
…………………100

= 934 yds

……………………………..934
So, Time required = ……….
……………………………..4.67

= 200 hr (ANS)

Problem-8:
Calculate the actual yarn consumption per month of weaving mil having 100 looms of 250 ppm for the following fabric construction. Considering each point.

80 x 60
……………..X 56”
..110 x 54

Production per month of 100 looms at 100% efficiency,

….250………………………….100
= …….. x (60 x 24 x 30) x …….
…..54…………………………….36

= 555556 yds

……………………………………….110 x 56 x 555556 x 1.05 x 1.1
Required amount of warp = …………………………………………
……………………………………………..840 x 80 x 2.204

= 26687 Kg

………………………………………….54 x 36 x 555556 x 56 x 1.05 x 1.1
Required amount of weft = ………………..…………………………………..
…………………………………………………36 x 840 x 60 x 2.204

= 17468 Kg (ANS)

Problem-9:
Find out thrust in Newton to drive a loom by using plate clutch system and conical clutch system. If F=425N, μ=0.45 and θ=20°

Solution:

………………………………F………425
For plate clutch, P = …….. = ………. = 944.44 Newton
………………………………µ………0.45

…………………………………………..F sin θ……425 sin 200
For conical clutch system, P = …………. = ………………… = 323.02 Newton (ANS)
………………………………………………..µ…………….0.45

Problem-10:
Calculate the production per shift of 10 hrs at 90% efficiency a weaving mill in average 22 picks per cm from the following information:

No. of looms ………..picks/cm ………PPM
120 ……………………20 ……………….220
16 ……………………..25 ………………..210
110 ………………….. 28 ………………. 200

………………………………………….220…………………….90………………1
Production at 22 picks/cm = ……… x (60 x 10) x …….. x 120 x ……. M
…………………………………………..20…………………….100…………….100

= 6480 m

………………………………………….220…………………..90…………..1
Production at 22 picks/cm = ……… x (60 x 10) x ….. x 16 x …….
……………………………………………20…………………..100…………100

= 824.73 m

…………………………………………220…………………….90…………….1
Production at 22 picks/cm = ………x (60 x 10) x ……. x 110 x …….
…………………………………………..20……………………100………….100

= 5400 m

Average production = (6480 + 824.734+5400) m

= 12704.73 m (ANS)

Problem-11:
Calculate the “speed space” required to produce a elastic fabric having 30% shrinkage (width of finished fabric 50″)
……………………………………………..130
Required reed space = 11 x 50 x ……..
……………………………………………..100

= 65 inch (ANS)

```Author of this Article:
Rofiquzzaman Raju
Fabric Technologist,
B.J.Group, Mawna, Gazipur
Chittagong Textile Engineering College
Contact: 01714419681```

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