# Mathematical Problem of Finisher Carding Machine

Finisher Carding Machine:
The finisher card is a fully circular and down sticking card. After jute is processed by breaker card, it is sent to finisher card. The rollers and cylinder are pinned in the same manner as in the breaker card but pins are finer and set closer together in the Finisher Carding machine.

In jute spinning, carding is the major area for the jute yarn production process. In the jute carding machine, the primary function of jute carding is done by the action of worker and cylinder and the cleaning and the cleaning actions are done between worker and stripper.

### Mathematical Problem of Finisher Carding Machine

Problem 1:
Calculate the wt of sliver in lbs/100Yds delivered from the finisher card from the data:

• B/C delivered sliver = 24 lbs/100 Yds
• F/C draft =15
• F/C doubling = 12
• Waste loss = 4%

Solution:

Wt of F/C delivers sliver/ Silver delivered per 100 Yds from F/C,

……………………………………Doubling……100 – waste%
= B/C delivered Sliver × ………………. ×…………………….
……………………………………….Draft……………..100

………….12……..100 -4
= 24 ×……. × ……………..
………….15………..100

=148.432 lbs. (Ans)

Problem: 2
Calculate wt of sliver in lb/100 Yds delivered from the

F/C B/C dollop wt =32 lb, B/C Clock length = 12.5 lb, B/C draft =10, F/C doubling =12, F/C draft =15.

Solution:
…………………………………………………………..32………..1
Sliver delivered per 100 Yds from B/C = ………..×………. ×100
…………………………………………………………..12.5……..10

= 25.6 lbs/100

…………………………………………………12……..100-4
Sliver delivered from F/C = 25.6× …….× ……………
………………………………………………….15………100

=19.66 lbs (ANS).

You may like also: Mathematical Problem of Breaker Carding Machine

Problem: 3
How many ends at the feed of the finisher card are required to obtain 14.22 lb/100 Yds sliver from finisher card with F/C draft=15, B/C sliver production =20 lb/ 100 Yds, M.R=3%

Solution:

Sliver delivery from F/C in-lbs/100 Yds,

…………………………………………………….F/C doubling…..100- loses
= Delivery from B/C in-lbs/100Yds ×………………….. × ………………
…………………………………………………………F/C draft…………..100

………………………F/C doubling…….100 -3
Or, 14.22 = 20×………………….. × ……………..
………………………………15……………….100

…………………………….14.22× 15×100
Or, F/C doubling = ……………………….
…………………………………20×97

=10.44 that means 11

11 ends will be required. (ANS)

```Author of this Article:
Engr Avijit Dey
Production Officer
Fabian Group, Chittagong
Mobile: 01836124490
E-mail: [email protected]```

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