# Production Calculation of Slasher Sizing Machine

Slasher Sizing:
Slasher sizing is the most used sizing process. In this process, the warp is passed through a size liquor bath then through a separating unit and cooling unit. This method is universally adopted and is suitable for large-scale operations. In this article, we will discuss the production calculation of the slasher sizing machine.

### Production Calculation of Slasher Sizing Machine

Problem-1:
The calculated production of a high-speed slasher is 100 yds per min. If the efficiency of the machine is 75%. Calculate

a) The actual production per day of 8 hrs.
b) The total length of yarn if the total ends in 3250 &
c) The total weight of the sized warp if it is sized to 10% & the count of the unsized yarn is 40s.

Solution:

Calculated production/day of 8 hrs = Calculated production/min in yds × 60 × 8
= 100 × 60 × 8 = 48000 yds.

a) The actual production per day of 8 hrs = Calculated production × efficiency
= 48000 × (75/100)
= 36000 yds. (ANS)

b) Total length of the yarn sized = Total length of warp × no. of ends
= 36000 × 3250
= 117000000 yds
=117000000/840
= 139286 hanks (ANS)

c) Weight of sized warp in lbs = (Length of the warp in hanks/Count) × 10%
= (139286/40) × 10%
= 3830 lbs (ANS)

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Problem-2:
A warp containing 2800 ends is required to be sized to 25%. The length of the sized warp on the beam is required to be 1080 yds. If the count of the yarn is the 40s then find –

a) The weight of the size to be put on the warp of the given length.
b) The weight of sized yarn.
c) The count of the sized warp.

Solution:

……………………………………………………….No. of ends X Required length on beam
Weight of 1080 yds of unsized warp =……………………………………………………………
…………………………………………………………………………..Count X 840

….2800 X 1080
= …………………..
…….40 X 840

= 90 lbs

Therefore,

a) Weight of size to be put = 90 × Size %
= 90 × 25%
= 22.5 lbs. (ANS)

b) The weight of the sized warp =Weight of unsized warp+Weight of size on it.
= 90 + 22.5
= 112.5 lbs. (ANS)

…………………………………………No. of ends X Required length on beam
c) The count of sized warp = ………………………………………………………….
……………………………………………The weight of the sized warp X 840

…..2800 X 1080
= …………………….
……112.5 X 840

= 32 ‘s (ANS)

```Author of this Article:
S. M. Hossen Uzzal
Production Officer
Monno Fabrics Ltd., Manikgonj
Email: uhossen@gmail.com```

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