# Direct System of Numbering Yarns and Calculations

Direct System of Yarn Count:
In this process, the count is based on the number of weight units in a length unit. Thus the size or bulkiness of the yarn is directly proportional to the count number. A coarser yarn will have a higher yarn count number while a finer yarn will have a lower count number. The system is used for very fine and very coarse yarns.

I have also published an article on “Indirect System of Yarn Numbering and Calculation” In the table below is given the length and weight units used in important direct systems.

Table:

### Direct System of Numbering Yarns and Calculations

Calculations:
We have,

……………….Weight in Appropriate unit
Count = ……………………………………………..                 ………. (1)
……………….Length in Appropriate unit
Therefore, by cross multiplication, we get the following:-

………………………………………….Weight in appropriate unit
Length in appropriate unit = ………………………………………..        ….. (2)
…………………………………………………………Count
Or,

Weight in appropriate unit = Length in appropriate unit X Count     ……..(3)

Denier System:

The weight unit is 1 denier and the length unit is a hank of 520 yards. In the English denier system, while 0.05 gram and 450 meters are the weight and length units respectively in the Metric denier system.

Therefore,
…………………………………………………….Weight in deniers
Count in English denier system = ………………………………….       ……….. (4)
……………………………………………………Length in yards/520

…………….Weight in deniers
= 520 X ……………..…………….           …….. (5)
………………Length in yards

……………………………………………………….Weight in grains / 0.82
Or, Count in English denier system = …………………………………….            ………. (6)
………………………………………………………….Length in yards / 520

…….520…………Weight in grains
= …………… X …………………………..                                                 ……… (7)
…….0.82………..Length in yards

………………………………………………..Weight in grammes / 0.05
Count in Metric denier system = …………………………………………..           ……….. (8)
…………………………………………………..Length in meters / 450

……450………….Weight in Grammes
= ………….. X ………………………………….
……0.05…………..Length in meters

……………….Weight in Grammes
= 9000 X ………………………………..                                                   …………. (9)
…………………Length in meters
By cross multiplication, we have:-

………………………………………..Weight in grams
Length in meters = 9000 X ………………………….                           ………… (10)
………………………………………………..Count
………………………………………Length in meters X Count
Or, Weight in grammes = …………………………………………                   ………….. (11)
……………………………………………………..9000

The metric denier system is more widely used than the English denier system. Example: 1. If 1350 meters of silk yarn weigh 7…. grammes, what is the count of the yarn metric denier system?

Solution:

Applying formula (3),

Weight in appropriate unit = Length in appropriate unit X Count

We have,

……………..450………..7.5
Count = ………. X ……………
……………..0.05……….1350

= 50 denier (ANS)

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Example 2: What is the weight of 270 meters of nylon yarn whose count is 200 denier (metric) ?

Solution:

Applying formula (8),

…………………………………………………..Weight in grammes / 0.05
Count in Metric denier system = ………………………………………………
……………………………………………………..Length in meters / 450
We have,

………………………………………………………………………….0.05
Weight in grammes = Count X Length in meters X …………
……………………………………………………………………………450

= 6 grams (ANS)

Example: 3. Calculate the count of 260 yards of rayon yarn which weighs 50 deniers.

Solution:
Applying the formula (4),

…………………………………………………..Weight in deniers
Count in English denier system = ……………………………….
…………………………………………………Length in yards/520

We have,

…………………50
Count = ………………
…………….260/520
= 100 deniers (English). (ANS)

```Author of this Article:
S.M. Bappy Rana
Dept. of Textile Engineering